How to skip first two lines and last one line in python

Question

I have string value:

    str1 = """
          first line
          second line
          abc
          def
          xyz
          123
          lastline"""

How to skip first two lines and last line and print remaining lines.

Code: I tried and works for to skip first two lines

for index, line in enumerate(str1.split("\n")):
    if index <= 1:
        continue
    print line

Output getting from above code:

          abc
          def
          xyz
          123
          lastline

Expected output:

          abc
          def
          xyz
          123

Answer 1

Use string.splitlines() :

>>> str1.splitlines()[3:-1]
['          abc', '          def', '          xyz', '          123']

Note that the first line (index 0) is empty. It is terminated by the first \\n directly after the opening double quotes.