I'm working with classes that have a lot of instance variables, and I want to have classes that inherit every instance variables from them. something like this:
class foo(object):
def __init__(self,thing1,thing2,thing3,thing4,thing5,thingetc):
self.1 = thing1
self.2 = thing2
self.3 = thing3
self.4 = thing4
self.5 = thing5
self.etc = thingetc
class bar(foo):
self.6 = []
a = bar
print a.3
obviously this won't work, but all the documentation that I can find on line is confusing. How do you inherit variables in cases like this?
Currently, your code is invalid syntax as a digit cannot be at the very front of a variable name. However, you can use *args
with __dict__
:
class foo:
def __init__(self, *args):
self.__dict__ = dict(zip(['var{}'.format(i) for i in range(1, len(args)+1)], args))
f = foo(*range(15))
print(f.var1)
print(f.var14)
Output:
0
13
Use this as a template for your inheritance, emphasis on the super() method:
class Foo:
def __init__(self):
self.name = 'Foo'
class Bar(Foo):
def __init__(self):
super().__init__()
b = Bar()
b.name
# outputs 'Foo'
For your specific type of class (that takes an unknown number of initialization arguments, ie *args ):
class Foo:
def __init__(self, *args):
self.name = 'Foo'
for i, arg in enumerate(args):
setattr(self, 'thing_' + str(i), arg)
class Bar(Foo):
def __init__(self, *args):
super().__init__(*args)
b = Bar('hello', 'world')
b.name
# outputs 'Foo'
b.thing_0
# outputs 'hello'
b.thing_1
# outputs 'world'
Now I would personally use the **kwargs
over *args
for specifying unique instance attributes:
class Foo:
def __init__(self, **kwargs):
self.name = 'Foo'
for att in kwargs:
setattr(self, att, kwargs[att])
class Bar(Foo):
def __init__(self, **kwargs):
super().__init__(**kwargs)
b = Bar(value = 4, area = 3.14)
b.name
# outputs 'Foo'
b.value
# outputs 4
b.area
# outputs 3.14
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