The question following is excerpted from exercise 6, chapter 7, A book on C.
Now there are two key points I do not understand about this question:
This question really makes no senses. One of the things I really hate about this book is, compared to C prorgamming written by Kochan, which I have no problems at all in understanding its questions, so dense to understand with respect to exercise questions. Or may be I am just stupid!
"every other bit" means each either bits 0, 2, 4, 6 ... or bits 1, 3, 5, 7 ...
If you start with 32 bits and take each other bit then your result is 16 bits.
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