Firstly, I am giving the codes. Then I am explaining the problem I am facing.
main.cpp
#include <iostream>
#include "acc.h"
using namespace std;
class mem;
int main()
{
show();
return 0;
}
acc.h
#ifndef ACC_H
#define ACC_H
#include "acc.cpp"
void show();
class mem{
int a;
public:
void showa();
void seta(int A);
};
#endif
acc.cpp
#include <iostream>
using namespace std;
void mem::showa(){cout<<a<<endl;}
void mem::seta(int A){a = A;}
void show()
{
mem m;
m.seta(22);
string ss;
cin>>ss;
cout<<"MY name is "<<ss<<" ";
m.showa();
}
"mem" class I declared in "acc.h" file already and added that "acc.h" into acc.cpp file also. But when I am calling that class from a function. It can't response. Showing "a" and "mem" not declared. How can I perfectly link that class definition and member functions of that class so that calling member functions of that class from another function can't create any problem?
If you remove the #include "acc.cpp"
from the acc.h
file it should compile without any errors. I tried and it compiles for me. I am using Visual Studio 2010 for the same.
Other than this, few more comments:
#pragma once
in you header file instead of #ifndef/#define
macros. The former is more cleaner. class mem
before main()
as you are already including acc.h
. show()
can be moved to where main()
is defined making the acc.h/acc.cpp
files dedicated for the mem
class. mem.h/mem.cpp
in your case. This informs which file contains which class even without opening the file.
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