How to get a result from a single array PHP

Question

How do I view a result from this array. For example if a user login with there Email address example1@example.com it should only show their info.

I have bean looking for an answer online with no luck. I find that my Array results dose not show a ID 1,2,3, may that be the reason for it not to work? can I create a ID with PHP or table? Or is it a simple code that I am missing. I have followed all the steps from www.w3schools.com for tables and PHP, and I still know I am missing something. I just don't see what it is yet. I am aware there may be a answer to this already, but I am having trouble finding it on Google for a answer as I don't know what to look for in the searches. Is there anything I can do?

As well, if you can direct me somewhere usefull for me to learn more that will be good as well.

Array
(
    [id] => 1
    [EmailAddr] => example1@example.com
    [Password] => 123456
    [client] => 555555
    [firstname] => first
    [lastname] => name
)

Array
(
    [id] => 2
    [EmailAddr] => example2@example.com
    [Password] => 987654
    [client] => 555556
    [firstname] => my
    [lastname] => name
)

Here is the code.

$sql = "SELECT id, EmailAddr, Password, client, firstname, lastname FROM table";
$result = $conn->query($sql);



if ($result->num_rows > 0) {
    // output data of each row

    while($row = $result->fetch_assoc()) {


      //  echo "id: " . $row["EmailAddr"]. " - Name: " . $row["firstname"]. " " . $row["lastname"]. "<br><br><br>";
    ?><pre><?print_r($row); ?></pre><?
    }
} else {
    echo "0 results";
}

Answer 1

Try this query:

SELECT id FROM mytable WHERE  EmailAddr='myemail@gmail.com';

where id is the value you want to pull out from the table. See https://www.w3schools.com/sql/sql_where.asp for more info.