Regex to match the last character if it is a dot

Question

In OpenOffice Calc how do I remove the last character if it is a dot?

Example:

dog
cat.
rabbit

It becomes:

dog
cat
rabbit

What regex would you use to obtain that?

Answer 1

Regular expression:

• To match a . , you have to write \\. , because . has a special meaning in regular expressions.
• To match the end of the line, you have to write $ .

Putting it all together, I would use this regular expression: \\.$ . This will match a dot if it's at the end of the line. Demo

Removing the matched dots:

1. Open "Find & Replace" window by pressing Ctrl+H
2. Type regular expression from above into "Search for" field, this is what you want to be replaced
3. Leave "Replace with" field empty, as you want to replace with nothing , which means it will remove the matched content (the dots)
4. Under "More/Other options" , turn on "Regular expressions "*
5. Click on "Replace" or "Replace all" button to perform the replacements

Please see documentation of this Calc feature for further details.

Answer 2

在OpenOffice Calc中，如果最后一个字符是点，该如何删除？

=IF(RIGHT(A1)=".";LEFT(A1;LEN(A1)-1);A1)