Given below, how do I write a function that will return a number less than 100?
const myArray = ['hello', 3, true, 18, 10,, 99 'ten', false]
const isLessThan100 = (array) => {
// how to do this? Solution enter here
}
I think it involves the filter method, but im not sure how to filter both a number less than 100, and is not a string.
Thanks in advance!
you can check if it is a number first like this
const myArray = ['hello', 3, true, 18, 10, 99, 'ten', false];
const isLessThan100 = myArray.filter(item => {
return (typeof item === "number") && item < 100;
});
The typeof operator returns a string indicating the type of the unevaluated operand.
You can first check whether the typeof
the item is number
or not, then check if it is less than 100
.
You can reduce the code to a single line by removing the curly braces.
Try Array.prototype.filter()
like the following way:
const myArray = ['hello', 3, true, 18, 10,, 99, 'ten', false] const isLessThan100 = (array) => array.filter(num => typeof(num) === "number" && num < 100); console.log(isLessThan100(myArray))
const isLessThan100 = (array)
Here's a short-ish one using filter :
const myArray = ['hello', 3, true, 18, 10, 99, 101, 'ten', false]; const isLessThan100 = a => a.filter(e => +e === e && e < 100); console.log(isLessThan100(myArray));
For getting only a single value, you could reduce the array.
const array = ['hello', 3, true, 18, 10,, 99, 'ten', false], isLessThan100 = array => array.reduce((r, v) => typeof v === 'number' && v < 100 && (typeof r !== 'number' || v > r) ? v : r, undefined); console.log(isLessThan100(array));
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