Javascript - Sort array of objects by date then by time

Question

I have the following array:

[{id: 1, value : "value1", date: "2018-08-08", time: "15:27:17"},
{id: 2, value : "value2", date: "2018-08-09", time: "12:27:17"},
{id: 3, value : "value3", date: "2018-08-10", time: "17:27:17"},
{id: 4, value : "value4", date: "2018-08-11", time: "10:27:17"}]

How can I go about sorting the array from earliest to latest or vice versa?

I tried sorting by date, but sorting it by time swaps the order of record id 4 to id 3, because it has an earlier time value than record 3, but is technically by definition, later.

Given this array and json structure, how do I sort the array to take both fields ( date and time ) into consideration?

Answer 1

Sort by the difference in the date s, and if there is no difference, sort by the difference in the time s, in a single .sort function:

 const arr = [{id: 1, value : "value1", date: "2018-08-08", time: "15:27:17"}, {id: 2, value : "value2", date: "2018-08-09", time: "12:27:17"}, {id: 3, value : "value3", date: "2018-08-10", time: "17:27:17"}, {id: 4, value : "value4", date: "2018-08-10", time: "01:27:17"}, {id: 5, value : "value5", date: "2018-08-10", time: "09:27:17"}, {id: 6, value : "value6", date: "2018-08-10", time: "23:27:17"}, {id: 7, value : "value7", date: "2018-08-10", time: "16:27:17"}, {id: 8, value : "value8", date: "2018-08-11", time: "10:27:17"} ]; arr.sort((a, b) => a.date.localeCompare(b.date) || a.time.localeCompare(b.time)); console.log(arr); 

The difference in dates will be returned, except if they're the same, in which case the localCompare will come out to 0 , and the difference in times will be returned instead.

To sort to descending instead, just switch the a s and b s:

 const arr = [{id: 1, value : "value1", date: "2018-08-08", time: "15:27:17"}, {id: 2, value : "value2", date: "2018-08-09", time: "12:27:17"}, {id: 3, value : "value3", date: "2018-08-10", time: "17:27:17"}, {id: 4, value : "value4", date: "2018-08-10", time: "01:27:17"}, {id: 5, value : "value5", date: "2018-08-10", time: "09:27:17"}, {id: 6, value : "value6", date: "2018-08-10", time: "23:27:17"}, {id: 7, value : "value7", date: "2018-08-10", time: "16:27:17"}, {id: 8, value : "value8", date: "2018-08-11", time: "10:27:17"} ]; arr.sort((a, b) => b.date.localeCompare(a.date) || b.time.localeCompare(a.time)); console.log(arr);