Im parsed list of crew witch one looks like:
20;mechanic;0;68
21;cook;0;43
22;scientist;0;79
23;manager;1;65
24;mechanic;1;41
etc
And now I'm trying to figure out how to count number of workers who have 60 or more stamina( the last element in each employee )
There is my code:
with open('employee.txt', 'r') as employee_list:
count = 0
for employee in employee_list.readlines():
employee_data = employee.rstrip().split(';')
if int(employee_data[3]) >= 60:
count += 1
print(count)
Print from terminal:
1
2
3
...
90
And there is the right answer I think, but is there anyway to get only one 'total' count, not a 90ty strings ?
Just print one line after the loop is done.
with open('employee.txt', 'r') as employee_list:
count = 0
for employee in employee_list.readlines():
employee_data = employee.rstrip().split(';')
if int(employee_data[3]) >= 60:
count += 1
print(count)
But I would also recommend using pandas
for data manipulation. For example:
df = pd.read_csv('employee.txt', sep=';')
df.columns = ['col1', 'col2', 'col3', 'stamina']
Then just filter and get the size:
df[df.stamina >= 60].size
So after a day of thinking I wrote this and get right answer ( maybe someone will find this helpful):
def total_resist_count():
# with open('employee.txt', 'r') as employee_list:
employee_list = [input() for i in range(120)]
candidates = []
for employee in employee_list:
employee_data = employee.rstrip().split(';')
if int(employee_data[3]) >= 60:
candidates.append(employee_data)
return candidates
required_professionals = {
'computers specialist': 5,
'cook': 3,
'doctor': 5,
'electrical engineer': 4,
'manager': 1,
'mechanic': 8,
'scientist': 14
}
expedition_total = 40
female_min = 21
male_min = 12
def validate_solution(cur_team, num_females, num_males):
global expedition_total, female_min, male_min
if sum(cur_team) != expedition_total or num_females < female_min or num_males < male_min:
return False
num_of_free_vacancies = 0
for k in required_professionals:
num_of_free_vacancies += required_professionals[k]
if num_of_free_vacancies > 0:
return False
return True
TEAM = None
def backtrack(candidates, cur_team, num_females, num_males):
global required_professionals, expedition_total, TEAM
if sum(cur_team) > expedition_total or TEAM is not None:
return
if validate_solution(cur_team, num_females, num_males):
team = []
for i, used in enumerate(cur_team):
if used == 1:
team.append(candidates[i])
TEAM = team
return
for i in range(len(candidates)):
if cur_team[i] == 0 and required_professionals[candidates[i][1]] > 0:
cur_team[i] = 1
required_professionals[candidates[i][1]] -= 1
if candidates[i][2] == '1':
backtrack(candidates, cur_team, num_females, num_males + 1)
else:
backtrack(candidates, cur_team, num_females + 1, num_males)
required_professionals[candidates[i][1]] += 1
cur_team[i] = 0
if __name__ == '__main__':
ec = decode_fcc_message()
candidates = total_resist_count(ec)
cur_team = [0] * len(candidates)
backtrack(candidates, cur_team, 0, 0)
s = ""
for t in TEAM:
s += str(t[0]) + ';'
print(s)
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