how do i print out every other character from a string in C?

Question

simplest way to print out every other character from a string in C? I already tried to loop through the array using

int main (void) 


for(int i = 0; i < strlen(input); i+=2)
{
    word[i] += input[i];
}

Answer 1

Why don't you just print it inside the loop?

for(int i = 0; i < strlen(input); i+=2)
{
    putchar(input[i]);
}

If you want to copy only each 2nd char into another array, your mistake is using the same index word[i] += input[i];

and as @bcperth mentioned, also using the += operator instead of a regular assignment '='

What you should have done is:

word[i/2] = input[i];

---

#include <stdio.h>
#include <string.h>

int main(void) {
    char* p = "hello world";
    char s[32] = "";

    for(int i = 0; i < strlen(p); i+=2){
        putchar(p[i]);
        s[i/2]=p[i];
    }

    printf("\n\n2nd option\n%s", s);
    return 0;
}

Output:

hlowrd

2nd option
hlowrd