JAVA Pass Primitive type as a Reference to function call

Question

I am newbie in java. I need to pass primitive type value as a reference in function call.I dont want to return i value from function because it already returns some object.

for (int i = 0; i < objects.size();) {
  // here it should fetch that object based on i manipulated in function
  Object obj = objects.get(i)
  Object node = someFunction(session,obj,i);
  // push node in nodes array
}
public Object someFunction(Session session,Object obj,int i){
   //manipulate i value based on condition
   if(true){
      i = i + 1;
   }else{
      i = i + 2;
   }
}

How i can achieve this as JAVA use pass by value in function call?

Thanks

Answer 1

In java primitive types always pass by value. To pass by reference you should define a class and put your primitive type in it. If you pass Integer class it doesn't work because this class is immutable and value doesn't change.

Answer 2

You can use a singular array of type int[] for a quick solution and increase its internal value. That doesn't change the array itself, only its content.

Answer 3

Are you aware of java streams? With streams you can do something like:

List<Object> result = objects.stream()
     .filter(object -> {/*add condition here*/})
     .map(object->{/*do something with object that match condition above*/})
     .collect(Collectors.toList()); 

You can use this mechanism to collect and process objects based on certain conditions.

If that doesn't help, maybe use an iterator?

Iterator<Object> it = objects.iterator();
while(it.hasNext()){
    Object node = someFunction(session,it);
}

public Object someFunction(Session session,Iterator i){
   //manipulate i value based on condition
   if(true){
      i.next();
   }else{
      i.next();
      i.next();
   }
}