This definition works:
const auto &b{nullptr};
while this fails:
auto *b{nullptr};
I have tried to compile this in Visual C++, GCC, and Clang. They all complain "cannot deduce type".
In the second case, shouldn't b
be deduced to have some type like std::nullptr_t
?
It's because you declare b
to be a pointer , and initialize it to be a null pointer. But a null pointer to what type of data you don't say, so the compiler can't deduce the type.
If you want b
to be a std::nullptr_t
object, you should drop the asterisk:
auto b{nullptr};
decltype(nullptr)
is std::nullptr_t
.
so with
const auto &b{nullptr}; // auto is std::nullptr_t
// b is a reference to a temporary (with lifetime extension)
but nullptr
is NOT a pointer (even if it is convertible to).
so auto *b{nullptr};
is invalid.
You might use instead
auto b{nullptr}; // auto is std::nullptr_t
nullptr
is of type std::nullptr_t
. As a nullptr
does not point to anything, there is no corresponding pointee type for std::nullptr_t
(you are not allowed to dereference a nullptr
), hence
auto *b { nullptr};
requests a type that does not exist. If you want b
to be of type nullptr_t
simply write
auto b { nullptr};
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