PHP/MySQL - Update array if variable does not exist

Question

I have an array with different IDs which I get from my database.

$fotos_temp_list=explode(",",$fotos_temp["fa_id"][0]);
Result: fa_id => 15,16,17,18

Now I want to update all rows inside another table with the IDs 15,16,17,18 and insert a specific '$id' into a column called 'fa_ev_id' . In this example I set:

$id=1;

Now my foreach-loop looks like this:

foreach ($fotos_temp_list as $key) {
    UPDATE images SET fa_ev_id = Concat(fa_ev_id , ',' ,'".$id."') where fa_id='".$key."' ";
}

This part is working too. Every row with my IDs (in my example: 15,16,17,18) gets updated.

Problem: When I run the foreach-loop again, the '$id' will be saved again inside the row. See here:

Question: How is it possible, that I can check if '$id' is already inside the row and if so, it gets skipped? Here is what I tried to do:

foreach ($fotos_temp_list as $key) {
    if (!in_array($id,$key)===true) {
        UPDATE fotoalbum SET fa_ev_id = Concat(fa_ev_id , ',' ,'".$id."') where fa_id='".$key."'
    }
}

I think the in_array function checks if '$id' id already inside '$key' and if it is true, the UPDATE statement is done. Therefore I added '!in_array' but it doesn´t seems to work. Does anyone has an idea what I am doing wrong? I just want to check if the '$id' is already inside my database row and if so, it should not insert the '$id' again. I appreciate any advice.

Answer 1

The in_array() function in php accepts an array as its second parameter, in (!in_array($id,$key)===true) , https://www.w3schools.com/php/func_array_in_array.asp . The second parameter $key , passed in here isn't an array.

You could save the datatype of fa_ev_id as json, and retrieve and json_decode the value when you are about performing an update the field to know if that $id already exists using in_array() or you could retrieve the values, expolode them to form an array and then check if it exists with in_array() .