How do I find the smallest, largest value and total and the average in a 2D list that the user provides in python?

Question

如何在用户在python中提供的2D列表中找到最小，最大值和总数以及平均值？

Answer 1

You can flatten it first.

a = [[1, 2], [3, 4]]
flattened = [num for sublist in a for num in sublist]
min_val = min(flattened)
max_val = max(flattened)
sum_val = sum(flattened)
avg_val = sum(flattened) / len(flattened)

So in your case it'll be:

def list_stats(a):
    flattened = [num for sublist in a for num in sublist]
    min_val = min(flattened)
    max_val = max(flattened)
    sum_val = sum(flattened)
    avg_val = sum_val / len(flattened)
    return min_val, max_val, sum_val, avg_val

#Testing
a = [[1.2,3.5],[5.5,4.2]]
small, large, total, average = list_stats(a)

Answer 2

This what I have so far:

    a = [[]]
    total = 0
    counter = 0 
    small = a[0][0]
    for i in a: 
        if i > small:
            return True 
            total += i 
            counter += 1 
    average = total / counter
    return small, large, total, average 

#Testing
a = [[1.2,3.5],[5.5,4.2]]
small, large, total, average = list_stats(a)

I'm getting the following two errors: small, large, total, average = list_stats(a) small = a[0][0] IndexError: list index out of range

The function list_stats is not defined.

a = [[]] is a list that contains an empty list. a[0][0] is an element that does not exist.

Answer 3

try this:

def list_stats(a):
    total = 0
    counter = 0 
    small = 99999
    large = -999
    for x in a:
        for y in x:
            if y < small: 
                small = y
            if y > large:
                large = y
            counter += 1
            total += y
    average = total / counter
    return small, large, total, average 

I like Eric's answer better