Sort an array of objects if property exists

Question

I have an array of objects. Out of each of these objects onle few of them have a property and I want to sort the array putting those objects at top which have that property.

Ex -

arr= [{key1: "obj1val1", key2 :"obj1val2"}, 
      {key2 :"obj2val2"}, 
      {key1: "obj3val3", key2 :"obj3val3"},
      {key2 :"obj4val1"},
      {key1: "obj5val1", key2 :"obj5val2"}
]

Sorted by key1

Expected Result - [{key1: "obj1val1", key2 :"obj1val2"}, 
                   {key1: "obj3val3", key2 :"obj3val3"},
                   {key1: "obj5val1", key2 :"obj5val2"}, 
                   {key2 :"obj2val2"}, 
                   {key2 :"obj4val1"}]

I have tried below approach-

sort : function(arr) {
              var copyArr = arr.slice();
              var newArr = [];
              for(var i=0; i<arr.length; i++){
                if(arr[i].key1){
                  newArr.push(arr[i]);
                    copyArr.splice(i, 1);
                }
              }
              Array.prototype.push.apply(newArr, copyArr);
              return newArr;
            }

Not exactly but I see discrepancy from the above approach. For a array bigger length, some of the objects which have key1 are not moved to top. Can this be done by internal sort method of javascript? If yes, how will the custom function compare ?

Can only support ES5 methods.

Answer 1

Can this be done by internal sort method of javascript

Yes: Simply prefer the entry that has the property:

arr.sort(function(left, right) {
    return left.hasOwnProperty("key1") ? -1 : right.hasOwnProperty("key1") ? 1 : 0
});

Live Example:

 var arr = [ {key1: "obj1val1", key2 :"obj1val2"}, {key2 :"obj2val2"}, {key1: "obj3val3", key2 :"obj3val3"}, {key2 :"obj4val1"}, {key1: "obj5val1", key2 :"obj5val2"} ]; arr.sort(function(left, right) { return left.hasOwnProperty("key1") ? -1 : right.hasOwnProperty("key1") ? 1 : 0 }); console.log(arr); 

If you also want to sort by that property's value:

arr.sort(function(left, right) {
    var leftHas = left.hasOwnProperty("key1");
    var rightHas = right.hasOwnProperty("key1");
    if (leftHas && rightHas) {
      return left.key1.localeCompare(right.key1);
    }
    return leftHas ? -1 : rightHas ? 1 : 0;
});

Live Example:

 var arr = [ {key1: "obj1val1", key2 :"obj1val2"}, {key2 :"obj2val2"}, {key1: "obj3val3", key2 :"obj3val3"}, {key2 :"obj4val1"}, {key1: "obj5val1", key2 :"obj5val2"} ]; arr.sort(function(left, right) { var leftHas = left.hasOwnProperty("key1"); var rightHas = right.hasOwnProperty("key1"); if (leftHas && rightHas) { return left.key1.localeCompare(right.key1); } return leftHas ? -1 : rightHas ? 1 : 0; }); console.log(arr); 

Answer 2

您可以采用的一种灵活方式：

arr.filter(obj => obj.hasOwnProperty('key1')).concat(arr.filter(obj => !obj.hasOwnProperty('key1')));

Answer 3

Here is a working snippet that gives your requested result and is easily extended. It uses the native array sort .

 arr = [{ key1: "obj1val1", key2: "obj1val2" }, { key2: "obj2val2" }, { key1: "obj3val3", key2: "obj3val3" }, { key2: "obj4val1" }, { key1: "obj5val1", key2: "obj5val2" } ] const sorted = arr.sort((a, b) => { const k1 = a.key1 === undefined ? 0 : 1 const k2 = b.key1 === undefined ? 0 : 2 return k2- k1 }) console.log(sorted) 

Answer 4

https://github.com/arraybrain/arraybrain

for complex array stuff, you can use it