So I am stuck with a problem here:
I have a pandas dataframe which looks like the following:
ID Name Value
0 Peter 21,2
1 Frank 24
2 Tom 23,21/23,60
3 Ismael 21,2/ 21,54
4 Joe 23,1
and so on...
What I am trying to is to split the "Value" column by the slash forward (/) but keep all the values, which do not have this kind of pattern.
Like here:
ID Name Value
0 Peter 21,2
1 Frank 24
2 Tom 23,21
3 Ismael 21,2
4 Joe 23,1
How can I achieve this? I tried the str.split method but it's not giving me the solution I want. Instead, it returns NaN as can be seen in the following.
My Code: df['Value']=df['value'].str.split('/', expand=True)[0]
Returns:
ID Name Value
0 Peter NaN
1 Frank NaN
2 Tom 23,21
3 Ismael 21,2
4 Joe Nan
All I need is the very first Value before the '/' is coming.
Appreciate any kind of help!
Remove expand=True
for return lists and add str[0]
for select first value:
df['Value'] = df['Value'].str.split('/').str[0]
print (df)
ID Name Value
0 0 Peter 21,2
1 1 Frank 24
2 2 Tom 23,21
3 3 Ismael 21,2
4 4 Joe 23,1
If performance is important use list comprehension:
df['Value'] = [x.split('/')[0] for x in df['Value']]
pandas.Series.str.replace
with regex df.assign(Value=df.Value.str.replace('/.*', ''))
ID Name Value
0 0 Peter 21,2
1 1 Frank 24
2 2 Tom 23,21
3 3 Ismael 21,2
4 4 Joe 23,1
Optionally, you can assign results directly back to dataframe
df['Value'] = df.Value.str.replace('/.*', '')
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