I need to write a bash script to list values from an sql database.
I've got so far but now I need to get the rest of the way.
The string so far is
10.255.200.0/24";i:1;s:15:"10.255.207.0/24";i:2;s:14:"192.168.0.0/21
I now need to delete everything between the speech marks and send it to a new line.
desired output:
10.255.200.0/24
10.255.207.0/24
192.168.0.0/21
any help would be greatly appreciated.
$ tr '"' '\n' <<< $string | awk 'NR%2'
10.255.200.0/24
10.255.207.0/24
192.168.0.0/21
You could use :
echo 'INPUT STRING HERE' | sed $'s/"[^"]*"/\\\n/g'
Explanation :
sed 's/<PATTERN1>/<PATTERN2/g'
: we substitute every occurrence of PATTERN1
by PATTERN2
[^"]*
: any character that is not a "
, any number of time \\\\\\n
: syntax for newline in sed ( reference here ) Considering that your Input_file is same as shown sample then could you please try following.
awk '
{
while(match($0,/[0-9]+\.[0-9]+\.[0-9]+\.[0-9]+\/[0-9]+/)){
print substr($0,RSTART,RLENGTH)
$0=substr($0,RSTART+RLENGTH)
}
}' Input_file
This might work for you (GNU sed):
sed 's/"[^"]*"/\n/g' file
Or using along side Bash:
sed $'/"[^"]*"/\\n/g' file
Or using most other sed's:
sed ':a;/"[^"]*"\(.*\)\(.\|$\)/{G;s//\2\1/;ba}' file
This uses the feature that an unadulterated hold space contains a newline.
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