I have calculated the differences of my data points and received this vector:
> diff(smooth$a)/(diff(smooth$b))
[1] -0.0099976150 0.0011162606 0.0116275973 0.0247594149 0.0213592319 0.0205187495 0.0179274056 0.0207752713
[9] 0.0231903072 -0.0077549224 -0.0401528643 -0.0477294350 -0.0340842051 -0.0148157337 0.0003829642 0.0160912230
[17] 0.0311189830
Now I want to get the positions (index) where I have a change from negative to positive when the following 3 data points are also positive.
So my output would be like this:
> output
-0.0099976150 -0.0148157337
How could I do this?
One way like this:
series <- paste(ifelse(vec < 0, 0, 1), collapse = '')
vec[gregexpr('0111', series)[[1]]]
#[1] -0.009997615 -0.014815734
The first line creates a sequence of 0s and 1s depending on the sign of the number. In the second line of the code we capture the sequence with gregexpr
. Finally, we use these indices to subset the original vector.
Imagine a vector z:
z <- seq(-2, 2, length.out = 20)
z
#> [1] -2.0000000 -1.7894737 -1.5789474 -1.3684211 -1.1578947 -0.9473684 -0.7368421 -0.5263158
#> [9] -0.3157895 -0.1052632 0.1052632 0.3157895 0.5263158 0.7368421 0.9473684 1.1578947
#> [17] 1.3684211 1.5789474 1.7894737 2.0000000
then you can do
turn_point <- which(z == max(z[z < 0]))
turn_plus_one <- c(turn_point, turn_point + 1)
z[turn_plus_one]
#> [1] -0.1052632 0.1052632
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