I want to write a function, which is given a set of vertices and then develops an edge between 2 vertices and repeats this until the graph becomes a connected graph). How can I tell when the graph has become connected?
This would be a basic idea: Every time you add a new edge, you run BFS or DFS to check the connectivity. This solution is can be further optimized.
import java.util.Deque;
import java.util.HashSet;
import java.util.LinkedList;
import java.util.Random;
import java.util.Set;
import org.jgrapht.graph.DefaultEdge;
import org.jgrapht.graph.SimpleGraph;
public class Main {
public static boolean isConnected(SimpleGraph<Integer, DefaultEdge> graph) {
Set<Integer> vertexSet = graph.vertexSet();
if(vertexSet.size()==0) {
//graph is connected by definition
return true;
}
if(vertexSet.size()-1>graph.edgeSet().size()) {
//not enough edges, must be disconnected
return false;
}
Set<Integer> traversed = new HashSet<>();
Deque<DefaultEdge> toTraverse = new LinkedList<DefaultEdge>();
//pick one random element to start search
Integer startVertex = vertexSet.iterator().next();
traversed.add(startVertex);
graph.edgesOf(startVertex).forEach(x->toTraverse.addLast(x));
while(traversed.size()!=vertexSet.size() && toTraverse.size()!=0) {
DefaultEdge currentEdge = toTraverse.pollFirst();
Integer src = graph.getEdgeSource(currentEdge);
Integer dst = graph.getEdgeSource(currentEdge);
//it can be at most one new vertex
Integer targetVertex = traversed.contains(src)?dst:src;
if(!traversed.contains(targetVertex)) {
traversed.add(targetVertex);
//BFS
graph.edgesOf(targetVertex).forEach(x->toTraverse.addLast(x));
//DFS
//graph.edgesOf(targetVertex).forEach(x->toTraverse.addFirst(x));
}
}
if(traversed.size()==vertexSet.size()) {
return true;
}else {
return false;
}
}
public static SimpleGraph<Integer, DefaultEdge> buildGraph(int numberOfVertices) {
SimpleGraph<Integer, DefaultEdge> g =
new SimpleGraph<Integer, DefaultEdge>(DefaultEdge.class);
for(int i = 0; i < numberOfVertices; i++) {
g.addVertex(i);
}
Random r = new Random();
do {
int a = r.nextInt(numberOfVertices);
int b = r.nextInt(numberOfVertices);
while(a == b) {
b = r.nextInt(numberOfVertices);
}
g.addEdge(a, b);
}while(!isConnected(g));
return g;
}
public static void main(String[] args) {
SimpleGraph<Integer, DefaultEdge> g = buildGraph(10);
System.out.println("Number of edges");
System.out.println(g.edgeSet().size());
System.out.println("Edges:");
for(DefaultEdge e: g.edgeSet()){
String a = g.getEdgeSource(e).toString();
String b = g.getEdgeTarget(e).toString();
System.out.println(a+" "+b);
}
}
}
For an arbitrary graph, checking connectivity requires at least O(V) (V - number of vertices, E - number of edges). BFS and DFS run in O(V+E). This might be fine if you want to create relatively small graphs. Here is a smarter idea how to do it. At the beginning you create V separate graphs. Now you want to add edge between A and B, you find the graph where A belongs and the other where B belongs. If those are two different graphs, merge them. Repeat this process until only one graph remains.
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