python syntax if in list function

Question

I am trying to find the proper python syntax to create a flag with a value of yes if columnx contains any of the following numbers: 1, 2, 3, 4, 5 .

def create_flag(df):
    if df['columnx'] in (1,2,3,4,5):
        return df['flag']=='yes'

I get the following error.

TypeError: invalid type comparison

Is there an obvious mistake in my syntax?

Answer 1

使用np.where与大熊猫isin为：

df['flag'] = np.where(df['columnx'].isin([1,2,3,4,5]),'yes','no')

Answer 2

You have lot of problems in your code! i assume you want to try something like this

def create_flag(df):
    if df['columnx'] in [1,2,3,4,5]:
        df['flag']='yes'

x = {"columnx":2,'flag':None}

create_flag(x)
print(x["flag"])