I am trying to fetch the rows from database where it start with a quote sign and do not end with quote sign. I have rows as follows in the Name column,
"TEXT
"TEXT"
"TEST
"TEST"
Desired output from select query,
"TEXT
"TEST
SQL query,
SELECT * FROM db.supplier where regexp_instr(Name_ ,'^[\"][\w-_.]+(?<!")') = 1;
I know the regex should be ending with $ to mark the end but it also didn't worked. Any suggestion is much appreciated.
How about using like
?
where Name_ like '"%' and Name_ not like '%"'
That seems simple enough. You could also use regexp_similar()
:
where regexp_similar(Name_, '^".*[^"]$')
Why are you using a negative lookbehind? This will return any values which start, but don't end with a double quote:
where regexp_similar(Name_ ,'".+[^"]') = 1
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