From below text in file:
current_build: 22
previous_build: 55
I am only trying to grep number value of current_build.
When run following command
grep -o -E '[0-9]+' textfile
The output is both number like below
22
55
How do i only grep the value 22
With GNU grep:
grep -Po 'current_build: \K.*' file
\\K
: removes matching part before \\K
Output:
22
I would use awk
because it is portable in opposite to grep -o
which only works with GNU grep:
awk '/current_build/{print $NF}' file
awk
splits the input into fields . The default field separator is a sequence of blank chars. NF
is the number of fields , $NF
is the last field.
仅在行首打印与current_build
匹配的行,并在最后一个空格之后显示部分:
sed -n 's/current_build:.* //p' file
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