How to check if Pandas column has value from list of string?

Question

I have a dataframe and a list

df = pd.DataFrame({'IDs':[1234,5346,1234,8793,8793],
                    'Names':['APPLE ABCD ONE','APPLE ABCD','NO STRAWBERRY YES','ORANGE AVAILABLE','TEA AVAILABLE']})

kw = ['APPLE ABCD', 'ORANGE', 'LEMONS', 'STRAWBERRY', 'BLUEBERRY', 'TEA COFFEE']

I want to create a new column flag such that if Names column contain keyword from kw , flag will be 1 else 0.

Expected Output:

    IDs     Names               Flag
0   1234    APPLE ABCD ONE      1
1   5346    APPLE ABCD          1
2   1234    NO STRAWBERRY YES   1
3   8793    ORANGE AVAILABLE    1
4   8793    TEA AVAILABLE       0

I am able to get the output using below code:

ind=[]
for idx, value in df.iterrows():
    x = 0
    for u in kw:
        if u in value['Names']:
            ind.append(True)
            x = 1
            break
    if x == 0:
        ind.append(False)

df['flag'] = ind

Is there an alternate way to avoid for loop and making it more efficient?

Answer 1

Use apply and lambda like:

df['Names'].apply(lambda x: any([k in x for k in kw]))

0     True
1     True
2     True
3     True
4    False
Name: Names, dtype: bool

Answer 2

您可以使用熊猫的isin函数

df['Names'].isin(kw)

Answer 3

Hi is it possible to return the value from list?

IDs Names Flag 0 1234 APPLE ABCD ONE APPLE 1 5346 APPLE ABCD APPLE 2 1234 NO STRAWBERRY YES STRAWBERRY 3 8793 ORANGE AVAILABLE ORANGE 4 8793 TEA AVAILABLE