After much searching, I can't seem to figure this out. Trying to write a function that:
Here is my function,
myfun <- function(db,var1, ...) {
var1 <- enquo(var1)
var2 <- quos(...)
for (i in var2) {
db %>%
group_by(!!var1) %>%
summarise(mean_var = mean(!!!var2))
}}
when I pass the following, nothing returns
myfun(data, group, age, bmi)
Ideally, I would like to group both age and bmi by group and return the mean and sd for each. In the future, I would like to pass many more columns from data into the function...
The output would be similar to summaryBy from doby package, but on many columns at once and would look like:
Group age.mean age.sd
0
1
bmi.mean bmi.sd
0
1
Your loop appears to be unnecessary (you aren't doing anything with i
). Instead, you could use summarize_at
to achieve the effect you want:
myfun <- function(db,var1, ...) {
var1 <- enquo(var1)
var2 <- quos(...)
db %>%
group_by(!!var1) %>%
summarise_at(vars(!!!var2), c(mean = mean, sd = sd))
}
And if we test it out with diamonds dataset:
myfun(diamonds, cut, x, z)
cut x_mean z_mean x_sd z_sd
<ord> <dbl> <dbl> <dbl> <dbl>
1 Fair 6.25 3.98 0.964 0.652
2 Good 5.84 3.64 1.06 0.655
3 Very Good 5.74 3.56 1.10 0.730
4 Premium 5.97 3.65 1.19 0.731
5 Ideal 5.51 3.40 1.06 0.658
To get the formatting closer to what you had in mind in your original post, we can use a bit of tidyr magic:
myfun <- function(db,var1, ...) {
var1 <- enquo(var1)
var2 <- quos(...)
db %>%
group_by(!!var1) %>%
summarise_at(vars(!!!var2), c(mean = mean, sd = sd)) %>%
gather(variable, value, -(!!var1)) %>%
separate(variable, c('variable', 'measure'), sep = '_') %>%
spread(measure, value) %>%
arrange(variable, !!var1)
}
cut variable mean sd
<ord> <chr> <dbl> <dbl>
1 Fair x 6.25 0.964
2 Good x 5.84 1.06
3 Very Good x 5.74 1.10
4 Premium x 5.97 1.19
5 Ideal x 5.51 1.06
6 Fair z 3.98 0.652
7 Good z 3.64 0.655
8 Very Good z 3.56 0.730
9 Premium z 3.65 0.731
10 Ideal z 3.40 0.658
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