How can I find visible only elements on a page with Selenium Webdriver?
Question
I got a page with couple hidden spans with same class. I need to check, if is one of them displayed on a page. I tried to use @driver.find_element(:class, 'some class').displayed? but it returns false , when visible span not first with that class on DOM. Is any way I can handle that?
UPDATE
HTML
<html>
<head></head>
<body>
<div class="span1" style="display: none;">
<span class="some class">Some Error</span>
</div>
<div class="span2" style="display: none;">
<span class="some class">Some Error</span>
</div>
<div class="span3" style>
<span class="some class">Some Error</span>
</div>
</body>
</html>
2 answers
solution1
1 2018-11-29 12:23:01
Instead of use style="display: none" you can use a CSS class for not display elements like:
.hidden {
display: none;
}
Now you can check if the element have this class.
UPDATE
If you can't change the HTML, may you can use the function element.isDisplayed() , does returns false if element have display: none or opacity: 0 , i found it in another question: How to check if an element is visible with WebDriver
solution2
0 2018-11-29 14:57:51
To check if any of the element is displayed on a page even when the visible <span> is not first within the parent node as per the HTML DOM you have provided, you can use the following solution:
Using XPath :
@driver.find_element(:xpath,"//span[@class='some class']").displayed?
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