So I'm developing a simple program that converts normal strings using the Caesar Cipher , which just shifts the letters of a string 3 times forward, and to decipher it, just undo it (pretty basic stuff), just as a simple test of my understanding of c++ (I am a beginner) and I am receiving an error not in my IDE (Code::Blocks), but instead in the console:
terminate called after throwing an instance of 'std::out_of_range'
what(): basic_string::at: __n (which is 1) >= this->size() (which is 0)
Here is my code:
#include <iostream>
#include <string>
using namespace std;
int main()
{
string input;
string conversion;
cin >> input;
for(unsigned int i = 1; i<input.length(); i++){
if(input.at(i) == 'a' || input.at(i) == 'A'){
conversion.at(i) = 'D';
}
if(input.at(i) == 'b' || input.at(i) == 'B'){
conversion.at(i) = 'E';
}
if(input.at(i) == 'c' || input.at(i) == 'C'){
conversion.at(i) = 'F';
}
if(input.at(i) == 'd' || input.at(i) == 'D'){
conversion.at(i) = 'G';
}
if(input.at(i) == 'e' || input.at(i) == 'E'){
conversion.at(i) = 'H';
}
if(input.at(i) == 'f' || input.at(i) == 'F'){
conversion.at(i) = 'I';
}
if(input.at(i) == 'g' || input.at(i) == 'G'){
conversion.at(i) = 'J';
}
if(input.at(i) == 'h' || input.at(i) == 'H'){
conversion.at(i) = 'K';
}
if(input.at(i) == 'i' || input.at(i) == 'I'){
conversion.at(i) = 'L';
}
if(input.at(i) == 'j' || input.at(i) == 'J'){
conversion.at(i) = 'M';
}
if(input.at(i) == 'k' || input.at(i) == 'K'){
conversion.at(i) = 'N';
}
if(input.at(i) == 'l' || input.at(i) == 'L'){
conversion.at(i) = 'O';
}
if(input.at(i) == 'm' || input.at(i) == 'M'){
conversion.at(i) = 'P';
}
if(input.at(i) == 'n' || input.at(i) == 'N'){
conversion.at(i) = 'Q';
}
if(input.at(i) == 'o' || input.at(i) == 'O'){
conversion.at(i) = 'R';
}
if(input.at(i) == 'p' || input.at(i) == 'P'){
conversion.at(i) = 'S';
}
if(input.at(i) == 'q' || input.at(i) == 'Q'){
conversion.at(i) = 'T';
}
if(input.at(i) == 'r' || input.at(i) == 'R'){
conversion.at(i) = 'U';
}
if(input.at(i) == 's' || input.at(i) == 'S'){
conversion.at(i) = 'V';
}
if(input.at(i) == 't' || input.at(i) == 'T'){
conversion.at(i) = 'W';
}
if(input.at(i) == 'u' || input.at(i) == 'U'){
conversion.at(i) = 'X';
}
if(input.at(i) == 'v' || input.at(i) == 'V'){
conversion.at(i) = 'Y';
}
if(input.at(i) == 'w' || input.at(i) == 'W'){
conversion.at(i) = 'Z';
}
if(input.at(i) == 'x' || input.at(i) == 'X'){
conversion.at(i) = 'A';
}
if(input.at(i) == 'y' || input.at(i) == 'Y'){
conversion.at(i) = 'B';
}
if(input.at(i) == 'z' || input.at(i) == 'Z'){
conversion.at(i) = 'C';
}
if(input.at(i) == ' '){
conversion.at(i) = ' ';
}
}
cout << conversion << endl;
return 0;
}
I don't understand how to fix the error, and I'd like help on fixing it.
You're trying to set characters in the string conversion
, which has zero length. That's why you get the error. All at()
calls on that string are invalid.
You need to first copy the input string into conversion
, and only then modify that. Or reserve
enough space and push_back
letters into it. Or simply use input
all along.
You can also do the “shift by 3” in a less verbose way, and respecting the case.
And you'd want to read an entire line of input at once, not just a single string – because such strings can never contain white space: that's the difference between getting a line vs just a string.
#include <iostream>
#include <string>
int main() {
using namespace std;
while (true) {
string input;
cout << "> " << flush;
if (!getline(cin, input) || input.empty()) return 0;
cin >> ws; // consume '\n'
for (char &c : input) {
char base = '\0';
if (c >= 'a' && c<= 'z') base = 'a';
else if (c >= 'A' && c <= 'Z') base = 'A';
if (base) {
c -= base;
c = (c + 3) % ('z' - 'a');
c += base;
}
}
cout << "< " << input << endl;
}
}
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