I have an SQL table with a column of names and a column of prices they paid for tickets. What query can I use to find the percentage of people who paid more than £100? Thanks
You can use avg()
to get the ratio:
select avg(case when price > 100 then 1.0 else 0 end)
from t;
select
100.0 -- to get a percentage
* count(case when price > 100 then 1 end) -- who paid over 100?
/ count(*) -- all rows
from tickets
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