Get the object with more properties from an array of objects

Question

Assuming I have the following array in a JSON file:

[
    { id: 1 },
    { name: 'foo' },
    { id: 3, name: 'foo', nick: 'bar' },
    { id: 4, nick: 'next' },
    { nick: 'nextnext' }
]

How to get the object with more properties? In this example I should get the third item: { id: 3, name: 'foo', nick: 'bar' }

If there is another object with 3 properties, I can get two results or the last found, it doesn't matter, my purpose is to know all properties an object can have.

Answer 1

To cope with multiple results, you could use filter.

 var data = [ { id: 1 }, { name: 'foo' }, { id: 3, name: 'foo', nick: 'bar' }, { id: 4, nick: 'next' }, { nick: 'nextnext' }, { id: 6, name: 'another 3', nick: '3'} ] const mx = Math.max(...data.map(m => Object.keys(m).length)); const res = data.filter(f => Object.keys(f).length === mx) console.log(res); 

Answer 2

You can use reduce and Object.keys() to return the object which has more length.

Try the following way:

 var data = [ { id: 1 }, { name: 'foo' }, { id: 3, name: 'foo', nick: 'bar' }, { id: 4, nick: 'next' }, { nick: 'nextnext' } ] var res = data.reduce((a, c) => { return Object.keys(a).length > Object.keys(c).length ? a : c; }) console.log(res); 

Answer 3

You can create an array and put values based on key length.

Since you want objects with most keys, you can get the last item.

 var data = [ { id: 1 }, { name: 'foo' }, { id: 3, name: 'foo', nick: 'bar' }, { id: 4, nick: 'next' }, { nick: 'nextnext' } ]; var res = data.reduce((a, c) => { const len = Object.keys(c).length; a[len] = a[len] || []; a[len].push(c); return a; }, []).pop(); console.log(res); 

Answer 4

let biggestObj = {};

for(let el of array){
    if(Object.keys(el).length > Object.keys(biggestObj).length){
        biggestObj = el;
    }
}

This should do the job!