Not sure how to solve this, need some help here.
Ajax call brings user information to servlet, I save user object in HttpSession and control goes back to Ajax from where i redirect control to next JSP page via controller servlet. However, if i try to retrieve object from HttpSession it is null .. not sure how to solve this issue.
here is my code for firstservlet:
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// get values from http request
// persist "user" object to database
HttpSession session = request.getSession(); //
session.setAttribute("user", user); //setting session variable
Gson gson = new Gson();
JsonElement jsonElement = null;
jsonElement = gson.toJsonTree("/nextservlet");
response.setContentType("text/plain");
PrintWriter out=response.getWriter();
}
here is my Javascript / AJAX code to redirect request to nextservlet
$.ajax({
type: 'POST',
url: ‘firstservlet’,
dataType: 'json',
contentType: 'application/json',
data: JSON.stringify(quiz),
success: function(result) {
//result = /nextservlet
window.location.href = result;
},
error:function(data,status,er) {
console.log("Error:",er);
}
});
and finally control comes to nextservlet - where i would like to process data and then show new JSP page.
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/plain");
response.setCharacterEncoding("UTF-8");
HttpSession session = request.getSession();
User user = session.getAttribute(“user”); //<--- this is NULL
LOG.warning("User id is : " + user.getId()); //<--- hence error here
RequestDispatcher dispatcher = request.getRequestDispatcher
("/anotherpage.jsp");
dispatcher.forward(request, response);
}
is issue because i am using -> window.location.href = result to send request to nextservlet .. and it goes to doGet??
I am not sure it but I see in Ajax
url: ‘firstservlet’,
type: 'POST'
and control goes to doGet method of nextservlet. It should be nextservlet of post method so use method doPost.
i'm not sure... but try it
success: function(result) {
// result = /nextservlet
var form = document.createElement('form');
form.action = result;
form.method = 'GET'
form.submit();
}
$.ajax({
type: 'POST',
url: '/firstservlet',
dataType: 'json',
contentType: 'application/json',
data: JSON.stringfy(quiz),
success: function(result) {
console.info(result);
var form = document.createElement('form');
form.action = result;
form.method = 'GET';
document.body.appendChild(form);
form.submit();
},
error: function(data, status, err) {
console.log("Error: ", err);
}
});
HttpSession session = request.getSession();
session.setAttribute("test", "test");
Gson gson = new Gson();
JsonElement jsonElement = gson.toJsonTree("/nextservlet");
response.setContentType("text/plain");
PrintWriter out = response.getWriter();
out.print(gson.toJson(jsonElement));
It can read session attribute in doGet Method try it.
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