I'm trying to click on the first image that appears for a given search in Flickr using Selenium as the code shows:
image = WebDriverWait(browser, 30).until(EC.element_to_be_clickable((By.XPATH, "//div[starts-with(@style,'transform: translate(0px, 0px)')]//a[@role='heading']")))
image.click()
I've tried doing it step by step in python's IDLE and it works flawlessly but when i run the script it raises a TimeoutException
as if the webelement never gets clickable. Any idea of what I am doing wrong ?
它不可点击,因为该元素与其他元素重叠并且需要hover
以使<a>
元素可点击,简单的解决方案是将条件更改为.presence_of_element_located()
As per the HTML DOM within the url to click on the first image that appears for a given search in Flickr using Selenium instead of using the style attribute I would suggest to use a more reliable attribute as follows:
Using CSS_SELECTOR
:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "div.view.photo-list-view>div.view.photo-list-photo-view.awake a.overlay[href*='photos']"))).click()
Using XPATH
:
WebDriverWait(browser, 30).until(EC.element_to_be_clickable((By.XPATH, "//div[@class='view photo-list-view']/div[@class='view photo-list-photo-view awake']//a[@class='overlay' and @role='heading'][contains(@href, 'photos')]"))).click()
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait from selenium.webdriver.common.by import By from selenium.webdriver.support import expected_conditions as EC
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