For parsing boolean command-line options using Python's built-in argparse
package, I am aware of this question and its several answers: Parsing boolean values with argparse .
Several of the answers (correctly, IMO) point out that the most common and straightforward idiom for boolean options (from the caller's point of view) is to accept both --foo
and --no-foo
options, which sets some value in the program to True
or False
, respectively.
However, all the answers I can find don't actually accomplish the task correctly, it seems to me. They seem to generally fall short on one of the following:
True
, False
, or None
). program.py --help
is correct and helpful, including showing what the default is. --foo
can be overridden by a later argument --no-foo
and vice versa; --foo
and --no-foo
are incompatible and mutually exclusive. What I'm wondering is whether this is even possible at all using argparse
.
Here's the closest I've come, based on answers by @mgilson and @fnkr:
def add_bool_arg(parser, name, help_true, help_false, default=None, exclusive=True):
if exclusive:
group = parser.add_mutually_exclusive_group(required=False)
else:
group = parser
group.add_argument('--' + name, dest=name, action='store_true', help=help_true)
group.add_argument('--no-' + name, dest=name, action='store_false', help=help_false)
parser.set_defaults(**{name: default})
parser = argparse.ArgumentParser(formatter_class=argparse.ArgumentDefaultsHelpFormatter)
add_bool_arg(parser, 'foo', "Do foo", "Don't foo", exclusive=True)
add_bool_arg(parser, 'bar', "Do bar", "Don't bar", default=True, exclusive=False)
That does most things well, but the help-text is confusing:
usage: argtest.py [-h] [--foo | --no-foo] [--bar] [--no-bar]
optional arguments:
-h, --help show this help message and exit
--foo Do foo (default: None)
--no-foo Don't foo (default: None)
--bar Do bar (default: True)
--no-bar Don't bar (default: True)
A better help text would be something like this:
usage: argtest.py [-h] [--foo | --no-foo] [--bar] [--no-bar]
optional arguments:
-h, --help show this help message and exit
--foo --no-foo Whether to foo (default: None)
--bar --no-bar Whether to bar (default: True)
But I don't see a way to accomplish that, since "--*" and "--no-*" must always be declared as separate arguments (right?).
In addition to the suggestions at the SO question mentioned above, I've also tried creating a custom action using techniques shown in this other SO question: Python argparse custom actions with additional arguments passed . These fail immediately saying either "error: argument --foo: expected one argument"
, or (if I set nargs=0
) "ValueError: nargs for store actions must be > 0"
. From poking into the argparse
source, it looks like this is because actions other than the pre-defined 'store_const', 'store_true', 'append', etc. must use the _StoreAction
class, which requires an argument.
Is there some other way to accomplish this? If someone has a combination of ideas I haven't thought of yet, please let me know!
(BTW- I'm creating this new question, rather than trying to add to the first question above, because the original question above was actually asking for a method to handle --foo TRUE
and --foo FALSE
arguments, which is different and IMO less commonly seen.)
One of the answers in your linked question , specifically the one by Robert T. McGibbon , includes a code snippet from an enhancement request that was never accepted into the standard argparse. It works fairly well, though, if you discount one annoyance. Here is my reproduction, with a few small modifications, as a stand-alone module with a little bit of pydoc string added, and an example of its usage:
import argparse
import re
class FlagAction(argparse.Action):
"""
GNU style --foo/--no-foo flag action for argparse
(via http://bugs.python.org/issue8538 and
https://stackoverflow.com/a/26618391/1256452).
This provides a GNU style flag action for argparse. Use
as, e.g., parser.add_argument('--foo', action=FlagAction).
The destination will default to 'foo' and the default value
if neither --foo or --no-foo are specified will be None
(so that you can tell if one or the other was given).
"""
def __init__(self, option_strings, dest, default=None,
required=False, help=None, metavar=None,
positive_prefixes=['--'], negative_prefixes=['--no-']):
self.positive_strings = set()
# self.negative_strings = set()
# Order of strings is important: the first one is the only
# one that will be shown in the short usage message! (This
# is an annoying little flaw.)
strings = []
for string in option_strings:
assert re.match(r'--[a-z]+', string, re.IGNORECASE)
suffix = string[2:]
for positive_prefix in positive_prefixes:
s = positive_prefix + suffix
self.positive_strings.add(s)
strings.append(s)
for negative_prefix in negative_prefixes:
s = negative_prefix + suffix
# self.negative_strings.add(s)
strings.append(s)
super(FlagAction, self).__init__(option_strings=strings, dest=dest,
nargs=0, default=default,
required=required, help=help,
metavar=metavar)
def __call__(self, parser, namespace, values, option_string=None):
if option_string in self.positive_strings:
setattr(namespace, self.dest, True)
else:
setattr(namespace, self.dest, False)
if __name__ == '__main__':
p = argparse.ArgumentParser()
p.add_argument('-a', '--arg', help='example')
p.add_argument('--foo', action=FlagAction, help='the boolean thing')
args = p.parse_args()
print(args)
(this code works in Python 2 and 3 both).
Here is the thing in action:
$ python flag_action.py -h
usage: flag_action.py [-h] [-a ARG] [--foo]
optional arguments:
-h, --help show this help message and exit
-a ARG, --arg ARG example
--foo, --no-foo the boolean thing
Note that the initial usage
message does not mention the --no-foo
option. There is no easy way to correct this other than to use the group method that you dislike.
$ python flag_action.py -a something --foo
Namespace(arg='something', foo=True)
$ python flag_action.py --no-foo
Namespace(arg=None, foo=False)
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