SQL Server : returning multiple rows by ROWID by using only one where / LIKE OPERATOR

Question

Here are rows in my database which I want to get:

I want to get get all 3 rows by executing one query, this ids are received as procedure parameters, sometimes I can receive 1 id and sometimes I can receive 10 of them, depends what users sends to database.

I wrote something like this:

SELECT * 
FROM Products
WHERE CONVERT(NVARCHAR(MAX), ProductId) LIKE '%' + 'A9472294-CFDD-40AC-BC2D-00E39AF4A300, 9A817E40-E4B1-4487-A376-010DD6377E38, 078A3C75-C442-4D88-A1E0-0118B8706667' + '%'

SELECT * 
FROM Products
WHERE 'A9472294-CFDD-40AC-BC2D-00E39AF4A300, 9A817E40-E4B1-4487-A376-010DD6377E38, 078A3C75-C442-4D88-A1E0-0118B8706667' LIKE '%' + CONVERT(NVARCHAR(MAX), ProductId) + '%' 

How come the second example returns rows as expected and the first example does not return any rows?

The definition says: %or% finds any values that have "or" in any position

How does this actually work? Could anyone explain?

EDIT:

I thought this LIKE operator should be used on my column like

Select * From Products Where ProductId Like '%' + 'SomeStringId' + '%';

because LIKE operator is used in a WHERE clause to search for a specified pattern in a column and my column is ProductId so I can't understand how come example like this works:

Select * From Products Where 'SomeStringId' Like '%' + ProductId + '%';

How come this example above works if Like is not used on my column, it's used on some string acctually...

Answer 1

You should split the string and then use an inner join.

For SQL Server below 2016 with the cumbersome string split via XML:

SELECT p.*
       FROM products p
            INNER JOIN (SELECT arg_xml_node.xml_node.value('(.)[1]', 'uniqueidentifier') uniqueidenfier
                               FROM (SELECT convert(xml,
                                            concat('<x>',
                                                   replace('A9472294-CFDD-40AC-BC2D-00E39AF4A300, 9A817E40-E4B1-4487-A376-010DD6377E38, 078A3C75-C442-4D88-A1E0-0118B8706667',
                                                           ', ',
                                                           '</x><x>'),
                                                   '</x>')) xml) arg_xml
                                    CROSS APPLY arg_xml.xml.nodes('x') arg_xml_node (xml_node)) arg_uniqueidenfier
                       ON arg_uniqueidenfier.uniqueidenfier = p.productid;

For SQL Server 2016 and above with the elegant way using string_split() :

SELECT p.*
       FROM products p
            INNER JOIN (SELECT convert(uniqueidentifier, ltrim(value)) uniqueidenfier
                               FROM string_split('A9472294-CFDD-40AC-BC2D-00E39AF4A300, 9A817E40-E4B1-4487-A376-010DD6377E38, 078A3C75-C442-4D88-A1E0-0118B8706667',
                                                 ',')) arg_uniqueidenfier
                       ON arg_uniqueidenfier.uniqueidenfier = p.productid;

db<>fiddle