finding two max values in Java

Question

Can anyone help me please? I want to find the maximum and the 2nd maximum value of an Array using a method. I already know how I can get the Minimum and the 2nd minimum value, it's basically almost the same, but the output is still wrong ? This is the method how I find the two minimum values.

public static void minimum( int [] a ) {
int min;
for (int i = 0; i< a.length; i++)  {
    for (int j = min = i; j< a.length; j++) {
        if (a[j] < a[min]) min = j;
        if(min>i) {
            int temp = a [i];
            a [i] = a [min];
            a [min] = temp;

        } 
}

so , to find the maximum I thought it's just to change < to > from this line : if (a[j] < a[min]) min = j;` so, instead of swapping smaller values, bigger values will be swapped. But it's wrong and I don't get it.

Thank you !

Answer 1

If you want to code by yourself,the code may help you:

public static void maxNum(int[] a) {
    int length = a.length;
    if (length == 0) {
        System.out.println("the length of input array 0");
        return;
    }
    if (length == 1) {
        System.out.println("the max is " + a[0]);
        return;
    }
    int max = a[0] > a[1] ? a[0] : a[1];
    int secondMax = a[0] > a[1] ? a[1] : a[0];
    for (int i = 2; i < length; i++) {
        int value = a[i];
        if (value > max) {
            int tmp = max;
            max = value;
            secondMax = tmp;
        } else if (value > secondMax) {
            secondMax = value;
        }
    }
    System.out.println("the max is " + max);
    System.out.println("the second max is " + secondMax);
}

If you don't want to code yourself,you can use tools in java like Arrays.sort() to sort the array first and get what you want.