Regex matching digit in between?

Question

I would like to get number in between these strings.

strings = ["point_right: account ISLAMIC: 860328 9221 asdsad",
       "account 723123123",
       "account823123213",
       "account 823.123.213",
       "account 823-123-213",
       "account:123213123 ",
       "account: 123213123 asdasdsad 017-299906",
       "account: 123213123",
       "point_right: account ISLAMIC: 860328 9221"
      ]

Result would be

[860328 9221,723123123, 823123213, 823.123.213, 823-123-213, 123213123, 123213123, 123213123]

And i can do processing later to make them into number. So far my strategy is to get everything after pattern and anything before a letter. I have tried:

for string in strings:
    print(re.findall("(?<=account)(.*)", string.lower()))

Please help to give some pointers on the regex match.

Answer 1

Try this pattern:

(?=[^0-9]*)[0-9][0-9 .-]*[0-9]

Breakdown:

• (?=[^0-9]*) Lookahead for a word, such as "account", non-matching
• [0-9] Find a digit
• [0-9 .-]* Find any number of digits or special characters (in your strings you have spaces, dashes, periods so I included those)
• [0-9] Find another digit (to prevent spaces at the end)

Check it out here , and sample code here

Answer 2

(?!\W)([\d\s.-]+)(?<!\s)

The negative lookahead and lookbehind seems like overkills here but I wasn't able to get a clean match otherwise. You may see the results here

(?!\\W) Negative lookahead to exclude any non-word characters [^a-zA-Z0-9_]

([\\d\\s.-]+) The capturing group for your numbers

(?<!\\s) Negative lookbehind to exclude whitespace characters [\\r\\n\\t\\f\\v ]

Answer 3

If the numbers must be the first numbers after the account substring use

re.findall("account\D*([\d\s.-]*\d)", s)

See the Python demo and the regex demo .

Pattern details

• account - a literal substring
• \\D* - 0+ chars other than digits
• ([\\d\\s.-]*\\d) - Capturing group 1 (the value returned by re.findall ): 0 or more digits, whitespaces, . and - chars followed with a digit.