Get first word after string

Question

I am using esp8266, i need to take first work isnide quotes after the word "+CWLAP:"

Here is my output result.

AT+CWLAP
+CWLAP:(3,"MainNetwork",-76,"00:15:6d:a6:61:fa",1,107,0,5,3,3,0)
+CWLAP:(1,"SubNetwork",-79,"00:4f:62:19:19:43",9,85,0,0,0,3,0)

OK

I need to print MainNetwork and subNetwork. Here is what i am trying to do

char *p =strtok(Receive.bytes, "+CWLAP:"); 

p = strtok(NULL,  "\"");
p = strtok(NULL,  "\"");
printf("%s\r\n",p);
__delay_ms(20);

p = strtok(NULL,  "+CWLAP:");
p = strtok(NULL,  "\"");
p = strtok(NULL,  "\"");
printf("%s\r\n",p);
__delay_ms(20);

For some reson i am taking this in my output

MainNetwork
,1,107,0,5,3,3,0)
+CWLAP:(1,

Answer 1

replace

char *p =strtok(Receive.bytes, "+CWLAP:");
p = strtok(NULL,  "\"");

by

char *p =strstr(Receive.bytes, "+CWLAP:"); 
p = strtok(p,  "\"");

because in your first strtok "+CWLAP:" is a string of separators, so strtok will give you AT placed before the '+'

is similar for the second but strtok add null characters so the second strstr must be done before any strtok .

A full solution can be :

  char * p1 = strstr(Receive.bytes, "+CWLAP:"); 
  char * p3 = strstr(p1 + 7, "+CWLAP:"); 
  char * p2;

  p2 = strtok(p1,  "\"");
  p2 = strtok(NULL,  "\"");
  printf("%s\r\n",p2);

  p2 = strtok(p3,  "\"");
  p2 = strtok(NULL,  "\"");
  printf("%s\r\n",p2);

Additional remark, strtok modify Receive.bytes adding null characters, may be you need first to duplicate the string ( strdup ) ?

Execution :

MainNetwork
SubNetwork

---

And to manage any number of lines :

char * p1 = strstr(Receive.bytes, "+CWLAP:");

while (p1 != NULL) {
  p1 += 7; /* bypass +CWLAP: */

  char * p2 = strstr(p1, "+CWLAP:");
  char * s = strtok(strchr(p1, '"') + 1,  "\"");

  printf("%s\r\n", s);

  p1 = p2;
}

I replaced the first strtok by a strchr because we don't need the intermediate string

Answer 2

Since strtok modifies the source array, strcspn can be used to iterate through the array along with strstr .
The search can be wrapped in a loop to find all the matches.
strstr will find an exact match of the sub-array in the source array.
From the match, strcspn will count the characters to next character in the source that matches any character in the delimiter string. Here only a quote is used as a delimiter. If strcspn does not find a match it counts to the terminating zero.
This prints the matching string but strncpy could be use to copy the string. Pay attention to the terminating zero.

#include <stdio.h>
#include <string.h>

int main()
{
    char bytes[] = "AT+CWLAP\n+CWLAP:(3,\"MainNetwork\",-76,\"00:15:6d:a6:61:fa\",1,107,0,5,3,3,0)\n+CWLAP:(1,\"SubNetwork\",-79,\"00:4f:62:19:19:43\",9,85,0,0,0,3,0)";
    char *quote = "\"";
    char *cwlap = "+CWLAP:";
    char *match = NULL;
    char *openquote = NULL;
    char *closequote = NULL;
    size_t skip = 0;
    size_t span = 0;

    closequote = bytes;
    while ( closequote && *closequote) {//not NULL and not zero terminator
        if ( ( match = strstr ( closequote, cwlap))) {//find exact sub-string match
            skip = strcspn ( match, quote);//count characters to quote
            openquote = match + skip;//point to quote
            if ( *openquote) {//not at terminating zero
                openquote++;//point to character after quote
                span = strcspn ( openquote, quote);//count characters to quote
                closequote = openquote + span;//point to quote
                if ( *closequote) {//not at terminating zero
                    printf ( "%.*s\n", (int)span, openquote);//print span number of characters
                    closequote++;//point to character after quote
                }
            }
            else {
                closequote = NULL;
            }
        }
        else {
            closequote = NULL;
        }
    }
    return 0;
}