TypeError: argument of type 'int' is not iterable (using lambda)

Question

 nb_products_per_basket['order_canceled'] =            
 nb_products_per_basket['InvoiceNo'].apply(lambda x:int('C' in x))

I have this :

TypeError: argument of type 'int' is not iterable

how can I fix it ?

Answer 1

There is problem one, multiple or all values are integers in column InvoiceNo .

Possible solution if mixed column values ( C are in another values not shown in sample data) is cast it to string s by astype :

nb_products_per_basket['order_canceled'] =            
nb_products_per_basket['InvoiceNo'].astype(str).apply(lambda x:int('C' in x))

Another solution with str.contains :

nb_products_per_basket['order_canceled'] =            
nb_products_per_basket['InvoiceNo'].str.contains('C', na=False).astype(int)

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If all values are integers there are no C , so always get 0 .