Javascript - Regular Expression with string template followed by 4 digits number?

Question

Good day. I wanna detect the url string in the <a> tag

<a href="http://virtualweb.test/en/?post_type=tribe_events&p=3642">Link</a>

whether it matchs the pattern : ?post_type=tribe_events&p=#### (#### = 4 digits number)

I'm writing some Jquery code to detect the expression but the console is throwing the error :

Invalid regular expression: /^(?)post_type=tribe_events&p=^(d{4})/: Invalid group

var str = $(a).attr("href");
var regexEx  = /^(?)post_type=tribe_events&p=^(d{4})/;
  var ok = regexEx.exec(str);
  console.log(ok);

I'm not good at the regex so I'd be aprreciated if there's any help.

Answer 1

There are couple of issues in your regex.

• You need to remove ^ from your regex which denotes start of string and in your case your string doesn't actually start from a ? and is in middle of the string.
• You need to escape ? as it has special meaning in regex which is zero or one occurrence of a character.
• You need to remove second ^ after p= which isn't needed
• You need to write \\d and not just d for representing a number.
• Also you don't need to group ? and \\d{4} unless you really need them.

You corrected regex becomes,

\?post_type=tribe_events&p=\d{4}

Demo

Answer 2

如果测试真的是你想要的，我想正确的语法是：

/^\?post_type=tribe_events&p=\d{4}/