I have an array like:
var participants = [
{username: "john", time: null},
{username: "samira", time: null},
{username: "mike", time: null},
{username: "son", time:null}
]
I want to remove an item by username:
const index = participants.map(x => {
x.map(y => {
return y.username;
})
}).indexOf(username); //get index of username
participants.splice(index, 1);
Hence, index of username returns "-1", therefore participants array becomes 0?
Expected output, by username: 'son':
[
{username: "john", time: null},
{username: "samira", time: null},
{username: "mike", time: null}
]
UPDATE:
Turns out my array is within an array, like this
您可以使用数组过滤器功能
participants.filter((item) => item.username !== username))
try this
var username = 'son';
for(var i = 0; i < participants.length; i++) {
if(participants[i].username == username) {
participants.splice(i, 1);
i--;
}
}
NOTE: filter
, map
and the like offer code readability while for
loops are better performing. Choose according to your specific problem.
您可以使用过滤器方法,也可以使用splice和map:
participants.splice(participants.map(x => x.username).indexOf(username),1);
You can use filter function, but filter doesn't change the original array; so you have to reassign results to the original variable. participants = participants.filter((item) => item.username !== username))
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.