The string method I want to use:
s.count(sub[, start[, end]])
A syntax error occurs at the first comma.
An error occurs at the first comma, so I checked several times if all the '[' signs or the ')' signs are used as a set(as in 'closed').
s = input("Enter a sentence that contains at least 4 words: ")
print("c) ", ljust(s, 50, fillchar='/'))
print("d)", s.count('oh'[, 1[, 5]]))
print("e)", s.index('oh'[, 1[, 5]]))
The first comma inside the count method shows an invalid syntax error. Just for your reference, I attached the line before and after the erroneous code, as well. Is there a parentheses that is not closed, or are there any errors besides the one I have thought about?
You're misreading the syntax of s.count
.
s.count(sub[, start[, end]])
What that means is that you call count
with the substring, optionally followed by a starting position (the [, start
portion), and if that optional start position is provided it can be followed by an optional end
(the [, end
portion). The two ]]
at the end before the closing parenthesis are the closures for the two optional portions.
What all that means is that you can call count
in any of these three ways:
By passing a substring only
s.count(sub)
By passing a substring and the place to start
s.count(sub, 5)
By passing a substring, the place to start, and the place to stop
s.count(sub, 5, 15)
(BTW, you're going to have the same issue for the same reason with s.index
on the next line once you correct this one.)
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