I'm trying to print the output of function only when it is true but so far all attempts have been unsuccsessful.
Something on the lines of:
let printFactor a b = if b then print_any((a,b))
Where b
is a boolean and a
is an integer. When I try it I get:
val printFactor : 'a -> bool -> unit
Any suggestions?
EDIT:
To put things in context im trying to use this with a pipe operator. Lets say I have a function xyz
that outputs a list of (int, bool). Id like to do something on these lines:
xyz |> printFactor
to print the true values only.
You could do eg this
let xyz() = [ (1,true); (2,false) ]
let printFactor (i,b) =
if b then
printfn "%A" i
xyz() |> List.iter printFactor
but it would probably be more idiomatic to do, eg this
xyz()
|> List.filter (fun (i,b) -> b)
|> List.iter (fun (i,b) -> printfn "%d" i)
that is, first filter, and then print.
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