I have a text similar to this:
Hello @[123456:Foo]
How to get '123456' and 'Foo' ?
My attempt:
@\[([\d+]):([\s+])\]
You may use
@\[(\d+):([^][]*)]
See the regex demo . The values you need are in Group 1 and 2.
Details
@\\[
- a @[
substring (\\d+)
- Capturing group 1: one or more digits :
- a colon ([^][]*)
- Capturing group 1: zero or more chars other than ]
and [
]
- a ]
char. C# demo:
var m = Regex.Match(str, @"@\[(\d+):([^][]*)]");
if (m.Success)
{
Console.WriteLine(m.Groups[1].Value);
Console.WriteLine(m.Groups[2].Value);
}
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