Remove all punctuation from string except for ' character

Question

Following this question How can I strip all punctuation from a string in JavaScript using regex? I'm trying to remove all punctuation from a string besides the ' character to avoid messing with words such as:

• wouldn't
• don't
• won't

So far I have tried the following:

return word.replace(/[^\w\s]|_\'/g, "")
          .replace(/\s+/g, " ");;

But it is still removing the ' character. Any idea how I can achieve such a result?

Answer 1

将转义的撇号移动到排除的字符类： /[^\\w\\s\\']|_/g

Answer 2

您可以使用此正则表达式

 console.log("I'm strong !".replace(/[.,\\/#!$%\\^&\\*;:{}=\\-_`~()]/g,"")) 

Answer 3

Add the apostrophe to your regex like this, in the exclusion block:

 const str = "This., -/is #! a ;: {} = - string$%^&* which `~)() doesn't, have any)( punctuation!"; const noPunctation = str.replace(/[^\\w\\s']|_/g, '').replace(/\\s+/g, ' '); console.log(noPunctation);