How to find nth minimum of a numpy array

Question

I want to find indices in ascending order of elements in last row in a 2D numpy array. An example is as below.

ti = np.array([[255, 2, 255, 9], [4, 255, 6, 255], [23, 11, 5, 18]])

# output = function(ti[-1])
# output : 2, 1, 3, 0

How do I achieve this? np.argmin only gives one minimum, and I could not find any other way including using partition (which returns sorted elements instead). Kindly help.

Answer 1

I tried np.argsort which sort of gives this output. Others please englighten if any more insights to be added.

np.argsort(ti[-1])

output:

array([2, 1, 3, 0], dtype=int64)