I want to store Date without time into my database. So, I choose to use LocalDate
type.
As mentioned in this article , I use a JPA converter to convert LocalDate
to Date
.
However, I have some troubles when I want to persist my entity (with POST and PUT requests).
Error
2019-02-23 11:26:30.254 WARN 2720 --- [-auto-1-exec-10] .w.s.m.s.DefaultHandlerExceptionResolver : Resolved [org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: Expected array or string.; nested exception is com.fasterxml.jackson.databind.exc.MismatchedInputException: Expected array or string.
at [Source: (PushbackInputStream); line: 1, column: 104] (through reference chain: ...entity.MyObject["startdate"])]
org.springframework.http.converter.HttpMessageConversionException: Type definition error: [simple type, class org.springframework.http.ResponseEntity]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `org.springframework.http.ResponseEntity` (no Creators, like default construct, exist): cannot deserialize from Object value (no delegate- or property-based Creator)
at [Source: (PushbackInputStream); line: 1, column: 2]
Code
Converter
package ...entity;
import javax.persistence.AttributeConverter;
import javax.persistence.Converter;
import java.time.LocalDate;
import java.sql.Date;
@Converter(autoApply = true)
public class LocalDateAttributeConverter implements AttributeConverter<LocalDate, Date> {
@Override
public Date convertToDatabaseColumn(LocalDate locDate) {
return (locDate == null ? null : Date.valueOf(locDate));
}
@Override
public LocalDate convertToEntityAttribute(Date sqlDate) {
return (sqlDate == null ? null : sqlDate.toLocalDate());
}
}
Entity
package ...entity;
import org.hibernate.annotations.ColumnDefault;
import javax.persistence.*;
import java.time.LocalDate;
import java.util.HashSet;
import java.util.Set;
@Entity
public class MyObject {
@Id
private String id;
private LocalDate startdate;
private LocalDate enddate;
public MyObject() {}
public MyObject(LocalDate enddate) {
this.startdate = LocalDate.now();
this.enddate = enddate;
}
...
}
"Main"
private DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
MyObject myobject = new MyObject(LocalDate.parse("2019-03-01", formatter));
Thanks for help.
EDIT 1 : Print of MyObject
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
HttpEntity<String> entity = new HttpEntity<>(this.toJsonString(myObject), headers);
System.out.println(entity.toString());
// <{"id":"ba6649e4-6e65-4f54-8f1a-f8fc7143b05a","startdate":{"year":2019,"month":"FEBRUARY","dayOfMonth":23,"dayOfWeek":"SATURDAY","era":"CE","dayOfYear":54,"leapYear":false,"monthValue":2,"chronology":{"id":"ISO","calendarType":"iso8601"}},"enddate":{"year":2019,"month":"MARCH","dayOfMonth":1,"dayOfWeek":"FRIDAY","era":"CE","dayOfYear":60,"leapYear":false,"monthValue":3,"chronology":{"id":"ISO","calendarType":"iso8601"}}},[Content-Type:"application/json"]>
With JPA 2.2, you no longer need to use converter it added support for the mapping of the following java.time types:
java.time.LocalDate
java.time.LocalTime
java.time.LocalDateTime
java.time.OffsetTime
java.time.OffsetDateTime
@Column(columnDefinition = "DATE")
private LocalDate date;
@Column(columnDefinition = "TIMESTAMP")
private LocalDateTime dateTime;
@Column(columnDefinition = "TIME")
private LocalTime localTime;
JPA 2.2 supports LocalDate
, so no converter is needed.
Hibernate also supports it as of 5.3 version.
Check out this article for more details.
Hibernate 5 supports java 8, so you can add this to your pom.xml:
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-java8</artifactId>
<version>5.1.0.Final</version>
</dependency>
This gives you mapping for LocalDate
and LocalDateTime
out of box.
JPA 2.2 added support for mapping Java 8 Date/Time API, like LocalDate
, LocalTime
, LocalDateTime
, OffsetDateTime
or OffsetTime
.
So, let's assume we have the following entity:
@Entity(name = "UserAccount")
@Table(name = "user_account")
public class UserAccount {
@Id
private Long id;
@Column(name = "first_name", length = 50)
private String firstName;
@Column(name = "last_name", length = 50)
private String lastName;
@Column(name = "subscribed_on")
private LocalDate subscribedOn;
//Getters and setters omitted for brevity
}
Notice that the subscribedOn
attribute is a LocalDate
Java object.
When persisting the UserAccount
:
UserAccount user = new UserAccount()
.setId(1L)
.setFirstName("Vlad")
.setLastName("Mihalcea")
.setSubscribedOn(
LocalDate.of(
2013, 9, 29
)
);
entityManager.persist(user);
Hibernate generates the proper SQL INSERT statement:
INSERT INTO user_account (
first_name,
last_name,
subscribed_on,
id
)
VALUES (
'Vlad',
'Mihalcea',
'2013-09-29',
1
)
When fetching the UserAccount
entity, we can see that the LocalDate
is properly fetched from the database:
UserAccount userAccount = entityManager.find(
UserAccount.class, 1L
);
assertEquals(
LocalDate.of(
2013, 9, 29
),
userAccount.getSubscribedOn()
);
我认为您可以编写自己的转换器,请检查答案: Spring Data JPA - 从字符串转换日期和/或时间时转换失败
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