def change():
if choice == 1: #<--- issue here
while True:
amt = float(input("Enter amount of cash: $"))
if amt >= a:
print("Your change will be: ${:.2f}".format(amt - a))
break
else:
print("Not enough, missing: ${:.2f}".format(a - amt))
input("press enter to continue")
a = 15.60
b = 56.12
c = 89.53
d = 32.93
print("1. a: $15.60\t\t\t2. b: $56.12\n3. c: $89.53\t\t\t4. d: $32.93")
choice = input("Choose product (1-4): ")
change()
If I remove line 2, it would function properly but choice 1 would not be selected. I'd like it so this would run while choice 1 is selected. For some reason it's not allowing me to put an if statement before while loop. Is there a solution?
It's the problem in your input statement. In python 3 input get default as string.So you need convert it to integer as below.
choice = int(input("Choose product (1-4): "))
在python 3.x中将字符串转换为整数使用int()
choice = int(input("Choose product (1-4): "))
Please try below code
def change():
print(choice, choice == 1, type(choice), int(choice) == 1)
if int(choice) == 1: #<--- issue here
while True:
amt = float(input("Enter amount of cash: $"))
if amt >= a:
print("Your change will be: ${:.2f}".format(amt - a))
break
else:
print("Not enough, missing: ${:.2f}".format(a - amt))
input("press enter to continue")
a = 15.60
b = 56.12
c = 89.53
d = 32.93
print("1. a: $15.60\t\t\t2. b: $56.12\n3. c: $89.53\t\t\t4. d: $32.93")
choice = input("Choose product (1-4): ")
change()
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.