How can I insert new row in a table using Hibernate?

Question

I'm trying to understand JPA/Hibernate, I'm able to create new database but I don't understand how insert new row in my database. This is the code:

import java.io.Serializable;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;

@Entity
public class Person implements Serializable {
    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;
    private String name;
    private String adress;
    private String phoneNumber;

    public void setName(String name) {
        this.name = name;
    }

    public void setAdress(String adress) {
        this.adress = adress;
    }

    public void setPhoneNumber(String phoneNumber) {
        this.phoneNumber = phoneNumber;
    }

    public String getName() {
        return name;
    }

    public String getAdress() {
        return adress;
    }

    public String getPhoneNumber() {
        return phoneNumber;
    }

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

   @Override
    public int hashCode() {
        int hash = 0;
        hash += (id != null ? id.hashCode() : 0);
        return hash;
    }

    @Override
    public boolean equals(Object object) {
        // TODO: Warning - this method won't work in the case the id fields are not set
        if (!(object instanceof Person)) {
            return false;
        }
        Person other = (Person) object;
        if ((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id))) {
            return false;
        }
        return true;
    }

    @Override
    public String toString() {
        return "entinty.Person[ id=" + id + " ]";
    }


}

The class that create the database is:

import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;

public class Main {

    public static void main(String args[]) {

        Person p = new Person();
        p.setName("xxx");
        p.setAdress("yyy");
        p.setPhoneNumber("zzz");
        EntityManagerFactory emf = javax.persistence.Persistence.createEntityManagerFactory("testPU");
        EntityManager em = emf.createEntityManager();
        em.getTransaction().begin();
        try {
            em.persist(p);
            em.getTransaction().commit();
        } catch (Exception e) {
            e.printStackTrace();
            em.getTransaction().rollback();
        }

        em.close();
        emf.close();



    }

}

At this point I have a table with one row (with written "xxx-yyy-zzz"). How can I add new row? Creating new Person doesn't work because it creates new table... I only find solution using Session and SessionFactory but I'm not able to use it, because I can't understand how generate a hibernate.cfg.xml (and in general how to create a session object). Is There a solution using only EntityManager? Or how can I generate/write a hibernate.cfg.xml file? Is there a way to generate automatically it using netbeans?

EDIT: this is my persistence.xml file. Where do I have to put the ? I put it in the *** zone but it doesn't work...

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
  <persistence-unit name="testPU" transaction-type="RESOURCE_LOCAL">
    <provider>org.hibernate.ejb.HibernatePersistence</provider>
    <class>test.Person</class>
    <properties>
      <property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/stackoverflow?zeroDateTimeBehavior=convertToNull"/>
      <property name="javax.persistence.jdbc.user" value="root"/>
      <property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver"/>
      <property name="javax.persistence.jdbc.password" value="leonida95."/>
      <property name="hibernate.cache.provider_class" value="org.hibernate.cache.NoCacheProvider"/>
      <property name="javax.persistence.schema-generation.database.action" value="create"/>
    *****
    </properties>
  </persistence-unit>
</persistence>

Answer 1

Inside your Persistence Unit file you'll have something like

<properties>
   <property name="hibernate.connection.url" value="..." />
   <property name="hibernate.connection.driver_class" value="..."/>
   ...
</properties>

To create tables when the EntityManagerFactory is constructed, just add

<property name="hibernate.hbm2ddl.auto" value="create" />

---

Your code works fine.
You can call persist as many times as you want, and it will add rows to the target table.

em.persist(person1);
em.persist(person2);
...

persist does not create a table.