简体   繁体   中英

Errorjava sql.SQLException: Parameter index out of range (1 >)

i have an error with my Code, but i don't know what is... (Java + MySQL)

public void deleteClientes(int nit){
   sql = "DELETE FROM `clientes` WHERE `clientes`.`nit` =  ";
   delete(sql,nit);

}

Method that receives:

 public void delete(String sql,int id){
    final QueryRunner qr = new QueryRunner(true); 
    try {
        qr.update(conexion(),sql,"%"+id+"%");
    } catch (SQLException ex) {
       System.err.println("Error"+ex);
    }
}

Your query doesn't have a placeholder ? . It should be:

"DELETE FROM `clientes` WHERE `clientes`.`nit` =  ?"

Need to add ? into sql statement where data will be placed based on parameter

sql = "DELETE FROM `clientes` WHERE `clientes`.`nit` =  ?";

and

 qr.update(conexion(),sql,id);

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM