How to detect if an array contains any value that is a specific length

Question

I have an array as follows:

var array = ['Bob','F', 'Nichols'];

I want to detect whether this array contains any values that are a single character long. In other words, I want to know whether there are any initials in this person's name.

var array = ['Bob','F', 'Nichols']; //true
var array = ['B','Freddy', 'Nichols']; //true
var array = ['Bob','Freddy', 'N']; //true
var array = ['B','F', 'N']; //true
var array = ['B','F', 'N']; //true
var array = ['Bob','Freddy', 'Nichols']; //false

if (anyInitials(array)) {
    console.log("there are initials");
} else {
    console.log("there are no initials");
}

function anyInitials(a) {
    var arrayLength = a.length;
    var initial = 'no';
        for (var i = 0; i < arrayLength; i++) {
            if (a[i].length == 1){
                initial = 'yes';
            }
        }
    return initial;
}

Answer 1

You can use the function some

 let array = ['Bob','F', 'Nichols']; console.log(array.some(({length}) => length === 1)); 

let anyInitials = a => a.some(({length}) => length === 1) ? "yes" : "no";

Answer 2

You can use a simple .forEach() loop like below. This loops through the array, and sets isInitial to true if the length is 1.

 var array = ['Bob', 'F', 'Nichols']; function anyInitials(a) { var isInitial = false; a.forEach(e => { if (e.length == 1) { isInitial = true; } }); return isInitial; } console.log(anyInitials(array)); 

You can also use .some() like below. This will return true if any element in the array has a length of 1.

 var array = ['Bob', 'F', 'Nichols']; function anyInitials(a) { return array.some(e => e.length == 1); } console.log(anyInitials(array));