remove all characters after last occurence of a pattern

Question

I'm parsing a txt file such as :

>scaffold_1:52559-5269(+):mus_musculus:15-207(+)
AAAGAAAATAATAAAGAAA
>scaffold_2:27092-2200(+):mus_musculus:0-105(+)
AAAGAAAATAAT

and the idea is to remove all part after the last : occurrence and get :

>scaffold_1:52559-5269(+):mus_musculus
AAAGAAAATAATAAA
>scaffold_2:27092-2200(+):mus_musculus
AAAGAAAATAAT

I know the sed command but not for the last occurence. Thanks for your help.

Answer 1

替换冒号，然后替换任意数量的非冒号。

sed 's/:[^:]*$//'

Answer 2

Another cut based:

$ cut -d : -f -3 file

Output:

>scaffold_1:52559-5269(+):mus_musculus
AAAGAAAATAATAAAGAAA
>scaffold_2:27092-2200(+):mus_musculus
AAAGAAAATAAT

Answer 3

A cut based solution :

while read line
do 
  echo "$line" | rev | cut -d: -f2- | rev 
done < file.txt