How to simplify ternary expression

Question

Is it possible to simplify this min + ternary expression by a one liner?

BigDecimal min = x.getMinimum();
BigDecimal result = otherValue.compareTo(min) > 0 ? otherValue : min;

Answer 1

Seems like you want BigDecimal.max .

BigDecimal result = otherValue.max(x.getMinimum());

This will give you whichever is the greater of otherValue and x.getMinimum() .

(If neither is greater than the other, it will return otherValue rather than x.getMinimum() , but that is probably close enough to what you want — the alternative would be x.getMinimum().max(otherValue) .)